Integrand size = 28, antiderivative size = 694 \[ \int \frac {\left (A+B x^2\right ) \left (d+e x^2\right )^2}{\left (a+c x^4\right )^{3/2}} \, dx=\frac {x \left (A c d^2-2 a B d e-a A e^2+\left (B c d^2+2 A c d e-a B e^2\right ) x^2\right )}{2 a c \sqrt {a+c x^4}}+\frac {B e^2 x \sqrt {a+c x^4}}{c^{3/2} \left (\sqrt {a}+\sqrt {c} x^2\right )}-\frac {\left (B c d^2+2 A c d e-a B e^2\right ) x \sqrt {a+c x^4}}{2 a c^{3/2} \left (\sqrt {a}+\sqrt {c} x^2\right )}-\frac {\sqrt [4]{a} B e^2 \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} E\left (2 \arctan \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{c^{7/4} \sqrt {a+c x^4}}+\frac {\left (B c d^2+2 A c d e-a B e^2\right ) \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} E\left (2 \arctan \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{2 a^{3/4} c^{7/4} \sqrt {a+c x^4}}+\frac {\sqrt [4]{a} B e^2 \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right ),\frac {1}{2}\right )}{2 c^{7/4} \sqrt {a+c x^4}}+\frac {e (2 B d+A e) \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right ),\frac {1}{2}\right )}{2 \sqrt [4]{a} c^{5/4} \sqrt {a+c x^4}}-\frac {\left (B c d^2+2 A c d e-a B e^2-\frac {\sqrt {c} \left (A c d^2-2 a B d e-a A e^2\right )}{\sqrt {a}}\right ) \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right ),\frac {1}{2}\right )}{4 a^{3/4} c^{7/4} \sqrt {a+c x^4}} \]
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Time = 0.33 (sec) , antiderivative size = 694, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.214, Rules used = {1735, 1193, 1212, 226, 1210, 311} \[ \int \frac {\left (A+B x^2\right ) \left (d+e x^2\right )^2}{\left (a+c x^4\right )^{3/2}} \, dx=-\frac {\left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right ),\frac {1}{2}\right ) \left (-\frac {\sqrt {c} \left (-a A e^2-2 a B d e+A c d^2\right )}{\sqrt {a}}-a B e^2+2 A c d e+B c d^2\right )}{4 a^{3/4} c^{7/4} \sqrt {a+c x^4}}+\frac {\left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} E\left (2 \arctan \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right ) \left (-a B e^2+2 A c d e+B c d^2\right )}{2 a^{3/4} c^{7/4} \sqrt {a+c x^4}}+\frac {e \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} (A e+2 B d) \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right ),\frac {1}{2}\right )}{2 \sqrt [4]{a} c^{5/4} \sqrt {a+c x^4}}-\frac {x \sqrt {a+c x^4} \left (-a B e^2+2 A c d e+B c d^2\right )}{2 a c^{3/2} \left (\sqrt {a}+\sqrt {c} x^2\right )}+\frac {x \left (x^2 \left (-a B e^2+2 A c d e+B c d^2\right )-a A e^2-2 a B d e+A c d^2\right )}{2 a c \sqrt {a+c x^4}}+\frac {\sqrt [4]{a} B e^2 \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right ),\frac {1}{2}\right )}{2 c^{7/4} \sqrt {a+c x^4}}-\frac {\sqrt [4]{a} B e^2 \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} E\left (2 \arctan \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{c^{7/4} \sqrt {a+c x^4}}+\frac {B e^2 x \sqrt {a+c x^4}}{c^{3/2} \left (\sqrt {a}+\sqrt {c} x^2\right )} \]
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Rule 226
Rule 311
Rule 1193
Rule 1210
Rule 1212
Rule 1735
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {A c d^2-2 a B d e-a A e^2+\left (B c d^2+2 A c d e-a B e^2\right ) x^2}{c \left (a+c x^4\right )^{3/2}}+\frac {e (2 B d+A e)}{c \sqrt {a+c x^4}}+\frac {B e^2 x^2}{c \sqrt {a+c x^4}}\right ) \, dx \\ & = \frac {\int \frac {A c d^2-2 a B d e-a A e^2+\left (B c d^2+2 A c d e-a B e^2\right ) x^2}{\left (a+c x^4\right )^{3/2}} \, dx}{c}+\frac {\left (B e^2\right ) \int \frac {x^2}{\sqrt {a+c x^4}} \, dx}{c}+\frac {(e (2 B d+A e)) \int \frac {1}{\sqrt {a+c x^4}} \, dx}{c} \\ & = \frac {x \left (A c d^2-2 a B d e-a A e^2+\left (B c d^2+2 A c d e-a B e^2\right ) x^2\right )}{2 a c \sqrt {a+c x^4}}+\frac {e (2 B d+A e) \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{2 \sqrt [4]{a} c^{5/4} \sqrt {a+c x^4}}-\frac {\int \frac {-A c d^2+2 a B d e+a A e^2+\left (B c d^2+2 A c d e-a B e^2\right ) x^2}{\sqrt {a+c x^4}} \, dx}{2 a c}+\frac {\left (\sqrt {a} B e^2\right ) \int \frac {1}{\sqrt {a+c x^4}} \, dx}{c^{3/2}}-\frac {\left (\sqrt {a} B e^2\right ) \int \frac {1-\frac {\sqrt {c} x^2}{\sqrt {a}}}{\sqrt {a+c x^4}} \, dx}{c^{3/2}} \\ & = \frac {x \left (A c d^2-2 a B d e-a A e^2+\left (B c d^2+2 A c d e-a B e^2\right ) x^2\right )}{2 a c \sqrt {a+c x^4}}+\frac {B e^2 x \sqrt {a+c x^4}}{c^{3/2} \left (\sqrt {a}+\sqrt {c} x^2\right )}-\frac {\sqrt [4]{a} B e^2 \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{c^{7/4} \sqrt {a+c x^4}}+\frac {\sqrt [4]{a} B e^2 \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{2 c^{7/4} \sqrt {a+c x^4}}+\frac {e (2 B d+A e) \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{2 \sqrt [4]{a} c^{5/4} \sqrt {a+c x^4}}+\frac {\left (B c d^2+2 A c d e-a B e^2\right ) \int \frac {1-\frac {\sqrt {c} x^2}{\sqrt {a}}}{\sqrt {a+c x^4}} \, dx}{2 \sqrt {a} c^{3/2}}-\frac {\left (B c d^2+2 A c d e-a B e^2-\frac {\sqrt {c} \left (A c d^2-2 a B d e-a A e^2\right )}{\sqrt {a}}\right ) \int \frac {1}{\sqrt {a+c x^4}} \, dx}{2 \sqrt {a} c^{3/2}} \\ & = \frac {x \left (A c d^2-2 a B d e-a A e^2+\left (B c d^2+2 A c d e-a B e^2\right ) x^2\right )}{2 a c \sqrt {a+c x^4}}+\frac {B e^2 x \sqrt {a+c x^4}}{c^{3/2} \left (\sqrt {a}+\sqrt {c} x^2\right )}-\frac {\left (B c d^2+2 A c d e-a B e^2\right ) x \sqrt {a+c x^4}}{2 a c^{3/2} \left (\sqrt {a}+\sqrt {c} x^2\right )}-\frac {\sqrt [4]{a} B e^2 \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{c^{7/4} \sqrt {a+c x^4}}+\frac {\left (B c d^2+2 A c d e-a B e^2\right ) \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{2 a^{3/4} c^{7/4} \sqrt {a+c x^4}}+\frac {\sqrt [4]{a} B e^2 \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{2 c^{7/4} \sqrt {a+c x^4}}+\frac {e (2 B d+A e) \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{2 \sqrt [4]{a} c^{5/4} \sqrt {a+c x^4}}-\frac {\left (B c d^2+2 A c d e-a B e^2-\frac {\sqrt {c} \left (A c d^2-2 a B d e-a A e^2\right )}{\sqrt {a}}\right ) \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{4 a^{3/4} c^{7/4} \sqrt {a+c x^4}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 10.14 (sec) , antiderivative size = 166, normalized size of antiderivative = 0.24 \[ \int \frac {\left (A+B x^2\right ) \left (d+e x^2\right )^2}{\left (a+c x^4\right )^{3/2}} \, dx=\frac {3 A \left (c d^2-a e^2\right ) x+6 a B e x \left (-d+e x^2\right )+3 \left (A c d^2+2 a B d e+a A e^2\right ) x \sqrt {1+\frac {c x^4}{a}} \operatorname {Hypergeometric2F1}\left (\frac {1}{4},\frac {1}{2},\frac {5}{4},-\frac {c x^4}{a}\right )+2 \left (B c d^2+2 A c d e-3 a B e^2\right ) x^3 \sqrt {1+\frac {c x^4}{a}} \operatorname {Hypergeometric2F1}\left (\frac {3}{4},\frac {3}{2},\frac {7}{4},-\frac {c x^4}{a}\right )}{6 a c \sqrt {a+c x^4}} \]
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Result contains complex when optimal does not.
Time = 1.55 (sec) , antiderivative size = 323, normalized size of antiderivative = 0.47
method | result | size |
elliptic | \(-\frac {2 c \left (-\frac {\left (2 A c d e -B a \,e^{2}+B c \,d^{2}\right ) x^{3}}{4 a \,c^{2}}+\frac {\left (a A \,e^{2}-A c \,d^{2}+2 a B d e \right ) x}{4 c^{2} a}\right )}{\sqrt {\left (x^{4}+\frac {a}{c}\right ) c}}+\frac {\left (\frac {e \left (A e +2 B d \right )}{c}-\frac {a A \,e^{2}-A c \,d^{2}+2 a B d e}{2 a c}\right ) \sqrt {1-\frac {i \sqrt {c}\, x^{2}}{\sqrt {a}}}\, \sqrt {1+\frac {i \sqrt {c}\, x^{2}}{\sqrt {a}}}\, F\left (x \sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}, i\right )}{\sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}\, \sqrt {c \,x^{4}+a}}+\frac {i \left (\frac {B \,e^{2}}{c}-\frac {2 A c d e -B a \,e^{2}+B c \,d^{2}}{2 a c}\right ) \sqrt {a}\, \sqrt {1-\frac {i \sqrt {c}\, x^{2}}{\sqrt {a}}}\, \sqrt {1+\frac {i \sqrt {c}\, x^{2}}{\sqrt {a}}}\, \left (F\left (x \sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}, i\right )-E\left (x \sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}, i\right )\right )}{\sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}\, \sqrt {c \,x^{4}+a}\, \sqrt {c}}\) | \(323\) |
default | \(d^{2} A \left (\frac {x}{2 a \sqrt {\left (x^{4}+\frac {a}{c}\right ) c}}+\frac {\sqrt {1-\frac {i \sqrt {c}\, x^{2}}{\sqrt {a}}}\, \sqrt {1+\frac {i \sqrt {c}\, x^{2}}{\sqrt {a}}}\, F\left (x \sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}, i\right )}{2 a \sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}\, \sqrt {c \,x^{4}+a}}\right )+B \,e^{2} \left (-\frac {x^{3}}{2 c \sqrt {\left (x^{4}+\frac {a}{c}\right ) c}}+\frac {3 i \sqrt {a}\, \sqrt {1-\frac {i \sqrt {c}\, x^{2}}{\sqrt {a}}}\, \sqrt {1+\frac {i \sqrt {c}\, x^{2}}{\sqrt {a}}}\, \left (F\left (x \sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}, i\right )-E\left (x \sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}, i\right )\right )}{2 c^{\frac {3}{2}} \sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}\, \sqrt {c \,x^{4}+a}}\right )+\left (A \,e^{2}+2 B e d \right ) \left (-\frac {x}{2 c \sqrt {\left (x^{4}+\frac {a}{c}\right ) c}}+\frac {\sqrt {1-\frac {i \sqrt {c}\, x^{2}}{\sqrt {a}}}\, \sqrt {1+\frac {i \sqrt {c}\, x^{2}}{\sqrt {a}}}\, F\left (x \sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}, i\right )}{2 c \sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}\, \sqrt {c \,x^{4}+a}}\right )+\left (2 A e d +B \,d^{2}\right ) \left (\frac {x^{3}}{2 a \sqrt {\left (x^{4}+\frac {a}{c}\right ) c}}-\frac {i \sqrt {1-\frac {i \sqrt {c}\, x^{2}}{\sqrt {a}}}\, \sqrt {1+\frac {i \sqrt {c}\, x^{2}}{\sqrt {a}}}\, \left (F\left (x \sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}, i\right )-E\left (x \sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}, i\right )\right )}{2 \sqrt {a}\, \sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}\, \sqrt {c \,x^{4}+a}\, \sqrt {c}}\right )\) | \(458\) |
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none
Time = 0.10 (sec) , antiderivative size = 332, normalized size of antiderivative = 0.48 \[ \int \frac {\left (A+B x^2\right ) \left (d+e x^2\right )^2}{\left (a+c x^4\right )^{3/2}} \, dx=-\frac {{\left ({\left (B a c^{2} d^{2} + 2 \, A a c^{2} d e - 3 \, B a^{2} c e^{2}\right )} x^{5} + {\left (B a^{2} c d^{2} + 2 \, A a^{2} c d e - 3 \, B a^{3} e^{2}\right )} x\right )} \sqrt {c} \left (-\frac {a}{c}\right )^{\frac {3}{4}} E(\arcsin \left (\frac {\left (-\frac {a}{c}\right )^{\frac {1}{4}}}{x}\right )\,|\,-1) - {\left ({\left (2 \, {\left (A + B\right )} a c^{2} d e + {\left (B a c^{2} + A c^{3}\right )} d^{2} - {\left (3 \, B a^{2} c - A a c^{2}\right )} e^{2}\right )} x^{5} + {\left (2 \, {\left (A + B\right )} a^{2} c d e + {\left (B a^{2} c + A a c^{2}\right )} d^{2} - {\left (3 \, B a^{3} - A a^{2} c\right )} e^{2}\right )} x\right )} \sqrt {c} \left (-\frac {a}{c}\right )^{\frac {3}{4}} F(\arcsin \left (\frac {\left (-\frac {a}{c}\right )^{\frac {1}{4}}}{x}\right )\,|\,-1) - {\left (2 \, B a^{2} c e^{2} x^{4} - B a^{2} c d^{2} - 2 \, A a^{2} c d e + 3 \, B a^{3} e^{2} + {\left (A a c^{2} d^{2} - 2 \, B a^{2} c d e - A a^{2} c e^{2}\right )} x^{2}\right )} \sqrt {c x^{4} + a}}{2 \, {\left (a^{2} c^{3} x^{5} + a^{3} c^{2} x\right )}} \]
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\[ \int \frac {\left (A+B x^2\right ) \left (d+e x^2\right )^2}{\left (a+c x^4\right )^{3/2}} \, dx=\int \frac {\left (A + B x^{2}\right ) \left (d + e x^{2}\right )^{2}}{\left (a + c x^{4}\right )^{\frac {3}{2}}}\, dx \]
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\[ \int \frac {\left (A+B x^2\right ) \left (d+e x^2\right )^2}{\left (a+c x^4\right )^{3/2}} \, dx=\int { \frac {{\left (B x^{2} + A\right )} {\left (e x^{2} + d\right )}^{2}}{{\left (c x^{4} + a\right )}^{\frac {3}{2}}} \,d x } \]
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\[ \int \frac {\left (A+B x^2\right ) \left (d+e x^2\right )^2}{\left (a+c x^4\right )^{3/2}} \, dx=\int { \frac {{\left (B x^{2} + A\right )} {\left (e x^{2} + d\right )}^{2}}{{\left (c x^{4} + a\right )}^{\frac {3}{2}}} \,d x } \]
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Timed out. \[ \int \frac {\left (A+B x^2\right ) \left (d+e x^2\right )^2}{\left (a+c x^4\right )^{3/2}} \, dx=\int \frac {\left (B\,x^2+A\right )\,{\left (e\,x^2+d\right )}^2}{{\left (c\,x^4+a\right )}^{3/2}} \,d x \]
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